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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決
Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決 
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三角函數廣義角的疑難!求解
Aug 25th 2014, 08:50

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tan&theta; = &ndash; 3/4 = 直線斜率 考慮&theta;大小的兩種情況為 sin&theta;=3/5 或 sin&theta; = &ndash; 3/5 則sin&theta;/(1--tan&theta;) =(3/5)/(1&ndash;(&ndash;3/4))或sin&theta;/(1--tan&theta;) =&ndash;(3/5)/(1&ndash;(&ndash;3/4)) 得sin&theta;/(1--tan&theta;) =12 / 35或 sin&theta;/(1<sep/>...
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